x^2+53x+360=0

Solution for x^2+53x+360=0 equation:

x^2+53x+360=0

a = 1; b = 53; c = +360;
Δ = b2-4ac
Δ = 532-4·1·360
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1369}=37$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(53)-37}{2*1}=\frac{-90}{2}
=-45
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(53)+37}{2*1}=\frac{-16}{2}
=-8
$